Two forces of 5⋅0 N each are acting on a point mass. If the angle between the forces is 60°, then the net force acting on the point mass has magnitude close to :

The correct answer is option "1"

Concept:

Parallelogram law of vector addition:

• If two vectors are acting simultaneously at a point, then it can be represented both in magnitude and direction by the adjacent sides of a parallelogram.
• The resultant vector is completely represented both in direction and magnitude by the diagonal of that parallelogram.

• The magnitude of the resultant vector is given as,

\(\Rightarrow R=\sqrt{A^{2}+B^{2}+2ABcosθ}\)

Where P and Q = magnitude of the two vectors, θ = angle between P and Q

CALCULATION:

Given A = B = 5 N, and θ = 60°

• The magnitude of the resultant vector is given as,

\(\Rightarrow R=\sqrt{A^{2}+B^{2}+2ABcosθ}\) -----(1)

\(\Rightarrow R=\sqrt{5^{2}+5^{2}+(2\times5\times5\times cos60)}\)

\(\Rightarrow R=5\sqrt3\,N\)

= 8.66 N

So, the net force acting on the point mass has magnitude close to 8.6 N