The relation between electric flux density (D) and field intensity (E) with absolute and relative permittivity is expressed as

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UPSC IES Electrical 2022 Prelims Official Paper
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  1. \(E=\frac{\epsilon_0 \epsilon_r}{D}\)
  2. \(E=\frac{D}{\epsilon_0 \epsilon_r}\)
  3. \(E=\frac{D\epsilon_0 }{\epsilon_r}\)
  4. \(E=\frac{D\epsilon_r }{\epsilon_0}\)

Answer (Detailed Solution Below)

Option 2 : \(E=\frac{D}{\epsilon_0 \epsilon_r}\)
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Electric field intensity (E): 

The space around an electric charge in which its influence can be felt is known as the electric field.

The electric field intensity at a point is the force experienced by a unit of positive charge placed at that point. 

Electric flux density (D): 

Electric flux density is a measure of the strength of an electric field generated by a free electric charge, corresponding to the number of electric lines of force passing through a given area.

Electric flux density is the amount of flux passing through a defined area that is perpendicular to the direction of the flux.

Relationship between D and E:

D = ϵE

D = ϵoϵE

\(E=\frac{D}{\epsilon_0 \epsilon_r}\)

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