If the electric field intensity is given by E̅ = (xux + yuy + zuz) V/m, the potential difference between X(2, 0, 0) and Y(1, 2, 3) is

This question was previously asked in
UPSC ESE (Prelims) Electronics and Telecommunication Engineering 19 Feb 2023 Official Paper
View all UPSC IES Papers >
  1. +1 V
  2. -1 V
  3. +5 V
  4. +6 V

Answer (Detailed Solution Below)

Option 3 : +5 V
Free
ST 1: UPSC ESE (IES) Civil - Building Materials
6.1 K Users
20 Questions 40 Marks 24 Mins

Detailed Solution

Download Solution PDF

Given that,

E = xux + yuy + zuz

X(2,0,0) Y(1,2,3)

Vyx = \(-\int^X_YE \cdot dl\)

\(-\displaystyle\int_{1,2,3}^{2,0,0} xdx + ydy+ zdz\)

\(-\frac{[x^2]_{1}^2 + [y^2]_2^0 +[z^2]_3^0}{2}\)

= +5V

Here, option 3 is correct.

Latest UPSC IES Updates

Last updated on May 28, 2025

->  UPSC ESE admit card 2025 for the prelims exam has been released. 

-> The UPSC IES Prelims 2025 will be held on 8th June 2025.

-> The selection process includes a Prelims and a Mains Examination, followed by a Personality Test/Interview.

-> Candidates should attempt the UPSC IES mock tests to increase their efficiency. The UPSC IES previous year papers can be downloaded here.

More Electrostatic Field Questions

Get Free Access Now
Hot Links: online teen patti real money teen patti dhani teen patti sweet