Question
Download Solution PDFThe radius of gyration about the polar axis of a circular lamina of radius 0.2 m is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The radius of gyration about the polar axis is given by:
\( k = \sqrt{\frac{J}{A}} \)
For a circular lamina:
- Polar moment of inertia, \( J = \frac{\pi R^4}{2} \)
- Area, \( A = \pi R^2 \)
Calculation:
\( k = \sqrt{\frac{\pi R^4 / 2}{\pi R^2}} = \sqrt{\frac{R^2}{2}} = \frac{R}{\sqrt{2}} \)
\( k = \frac{0.2}{\sqrt{2}} \approx 0.141~\text{m} \approx 0.14~\text{m} \)
Last updated on Jun 7, 2025
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