The quadratic equation whose roots are 2 and \(-\frac{1}{2}\) is :

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RRB Group D 9 Sept 2022 Shift 3 Official Paper
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  1. 3x2 - 3x - 2 = 0
  2. 2x2 - 3x - 2 = 0
  3. 2x2 - 5x - 2 = 0
  4. 5x2 - 3x - 2 = 0

Answer (Detailed Solution Below)

Option 2 : 2x2 - 3x - 2 = 0
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Detailed Solution

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Given:

Quadratic roots are 2 and  \(-\frac{1}{2}\) 

Formula used:

Sum of the roots

Product of roots

Calculation:

Let the roots be m and  n 

According to the question,

m = 2 and n = \(-\frac{1}{2}\) 

Now, sum of roots = m + n = 2 + (\(-\frac{1}{2}\) )

sum of roots = \(3\over2\)

Product of roots = mn = 2 × \(-\frac{1}{2}\) 

Product of roots = - 1

Now, put the values in the quadratic equation formula,

x2 - (m + n)x + mn = 0

x2 - \(3\over2\)x - 1 = 0

On solving we get,

2x2 - 3x - 2 = 0

Hence, this is the correct option 2x2 - 3x - 2 = 0.

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