The mean free path of gas molecules is proportional to nth power of diameter of molecules. Here n is

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Official Sr. Teacher Gr II NON-TSP Science (Held on : 1 Nov 2018)
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  1. \(\dfrac{1}{2}\)
  2. \(-\dfrac{1}{2}\)
  3. 2
  4. -2

Answer (Detailed Solution Below)

Option 4 : -2
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CONCEPT:

Mean Free Path (λ): 

F1 P.Y 4.9.20 Pallavi D7

  • The distance travelled by a gas molecule between two successive collisions is known as a free path.
    \(λ = \frac{{Total\;distance\;travelled\;by\;a\;gas\;molecule\;between\;successive\;collisions\;\;}}{{Total\;number\;of\;collisions}}\)
  • During two successive collisions, a molecule of gas moves in a straight line with constant velocity, and the mean free path of a gas molecule is given by
    \(λ = \frac{1}{{\sqrt 2 \pi n{d^2}}}\)

Where n = number of molecules per unit volume and d = diameter of a molecule

EXPLANATION:

  • The mean free path of a gas molecule is given by

\(⇒ λ = \frac{1}{{\sqrt 2 \pi n{d^2}}}\)

⇒ λ ∝ d-2

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