The limiting molar conductivities, at 25°C, of few ionic compounds are given in the table below. The limiting molar conductivity of Agl, in units of milli-Siemens (metre)² mol^-1, at 25°C is

Ionic Compound	Molar conductivity (milli-Siemens (metre)2 mo-1)
Nal	12.69
NaNO3	12.16
AgNO3	13.34

Concept:

• Kohlrausch’s Law: The equivalent conductance of an electrolyte at infinite dilution is equal to the sum of the equivalent conductances of the component ions.
• The molar conductivity of a solution at infinite dilution is known as limiting molar conductivity.
• In other words, When the concentration of the electrolyte approaches zero, the molar conductivity is known as limiting molar conductivity.

Explanation:

The limiting molar conductivity of Agl, in units of milli-Siemens (metre)2 mol-1, at 25°C is

\(\Lambda _{NaI}^{\circ }= \Lambda _{Na^{+}}^{\circ } + \Lambda _{I^{-}}^{\circ }\)= 12.69 ......(1)

\(\Lambda _{NaNO_3}^{\circ }=\Lambda _{Na^{+}}^{\circ } + \Lambda _{NO_3^{-}}^{\circ }\)= 12.16 .........(2)

\(\Lambda _{AgNO_3}^{\circ }=\Lambda _{Ag^{+}}^{\circ } + \Lambda _{NO_3^{-}}^{\circ }\) = 13.34.......(3)

Now, \(\Lambda _{AgI}^{\circ }= \Lambda _{Ag^{+}}^{\circ } + \Lambda _{I^{-}}^{\circ }\)

On applying operation, eq. (1+3-2), we get

\(\Lambda _{AgI}^{\circ }= \Lambda _{Ag^{+}}^{\circ } + \Lambda _{I^{-}}^{\circ }\)

\(=\Lambda _{Na^{+}}^{\circ } + \Lambda _{I^{-}}^{\circ }+\Lambda _{Ag^{+}}^{\circ } + \Lambda _{NO_3^{-}}^{\circ }-(\Lambda _{Na^{+}}^{\circ } + \Lambda _{NO_3^{-}}^{\circ })\)

=12.69 + 13.34 - 12.16

= 13.87 (milli-Siemens (metre)2 mo-1)

Conclusion:

Hence, the limiting molar conductivity of Agl, in units of milli-Siemens (metre)2 mol-1, at 25°C is 13.87