The electric potential at point A is 60 V and at B is - 90 V. Find the work done by an external force and electrostatic force, respectively, in moving an electron slowly from B to A.

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SSC JE Electrical 16 Nov 2022 Shift 3 Official Paper
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  1. 240 × 10-19 J and 240 × 10-19 J
  2. Zero and 240 × 10-19 J
  3. -240 × 10-19 J and 240 × 10-19 J
  4. 240 × 10-19 J and zero

Answer (Detailed Solution Below)

Option 3 : -240 × 10-19 J and 240 × 10-19 J
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Detailed Solution

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The correct answer is option 3):(-240 × 10-19 J and 240 × 10-19 J)

Concept:

The work done by an external force to move a change from one point to another point is given

W = q ΔV

where

charge of electron

q = −1.6×10 −19  C 

ΔV is the change in potential 

The electrostatic potential energy is

U = - W

Calculation:

q = −1.6×10 −19  C 

Potential at A is 60 V

Potential at  B is - 90 V

W = −1.6×10 −19( 60+ 90)

= - 240 ×10 −19 J

The electrostatic potential energy is

U = 240 ×10 −19 J

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