The electric field lines due to a certain charge is as shown in the figure. If and A and B are two arbitrary points within the electric field such that the electric field intensity at point A and B are E_A and E_B respectively. Then the correct statement is:

The correct answer is option 1) i.e. EA > EB 

CONCEPT:

• Electric field strength is a measure of the electric field intensity at a point due to a charge. It is the amount of electric force produced per unit charge.

Electric field strength (E) at a point due to a point charge q is given by the formula:

\(E =\frac{q}{4\pi \epsilon_0 r^2}\)
q4πϵ0r2

Where r is the distance from the point charge to the point at which E is determined.

• Electric field lines: An electric field line is defined as an imaginary curve drawn in such a way that the tangent to it at each point gives the direction of the net electric field at that point. They are the visual representation of the electric field as lines.

EXPLANATION:

• The electric field intensity at a point r from the point charge, 

​\(E \propto\frac {1}{r^2}\)

• Therefore, as the distance increases from the charge, the intensity of the electric field decreases.
• In the given question, point B is farther than point A. Hence, electric field intensity at A will be greater than that at B. 

⇒ EA > EB