The distance of the point (2, 3, 4) from the plane 3x - 6y + 2z + 11 = 0 is

Question

Question

Answer 1

CONCEPT:

Perpendicular distance of a plane ax + by + cz + d = 0 from a point P (x₁, y₁, z₁) is given by:

CALCULATION:

Here, we have to find the distance of the point (2, 3, 4) from the plane 3x - 6y + 2z + 11 = 0

As we know that, the perpendicular distance of a plane ax + by + cz + d = 0 from a point P (x1, y1, z1) is given by:

Here, x₁ = 2, y₁ = 3, z₁ = 4, a = 3, b = - 6 and c = 2

So, the required distance between the given point and plane is

⇒ D = 1

Hence, option A is the correct answer.