Question
Download Solution PDFThe distance of centre of pressure from free surface of liquid is independent of:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept-
- The point at which the total pressure is supposed to act is called as the center of pressure.
- It is denoted by h and it is given as, h = \(\bar x + \frac{{{I_G}}}{{A\bar x}} \times {\sin ^2}θ \)
- Where, \(\bar x\) = Center of gravity from the free surface,IG =Moment of inertia of the object
- A = Area of object
- θ = angle of the submerged plate in fluid with a free surface
- In the above formula, it clearly shows that the depth of the center of pressure is not dependent on the density of the fluid.
Last updated on May 28, 2025
-> SSC JE ME Notification 2025 will be released on June 30.
-> The SSC JE Mechanical engineering application form will be available from June 30 to July 21.
-> SSC JE 2025 CBT 1 exam for Mechanical Engineering will be conducted from October 2 to 31.
-> SSC JE exam to recruit Junior Engineers in different disciplines under various departments of the Central Government.
-> The selection process of the candidates for the SSC Junior Engineer post consists of Paper I, Paper II, Document Verification, and Medical Examination.
-> Candidates who will get selected will get a salary range between Rs. 35,400/- to Rs. 1,12,400/-.
-> Candidates must refer to the SSC JE Previous Year Papers and SSC JE Civil Mock Test, SSC JE Electrical Mock Test, and SSC JE Mechanical Mock Test to understand the type of questions coming in the examination.