Question
Download Solution PDFThe constraints –x + y ≤ 1, −x + 3y ≤ 9 and x, y ≥ 0 defines on
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
First, graph the "equals" line, then shade in the correct area.
There are three steps:
- Rearrange the equation so "y" is on the left and everything else on the right.
- Plot the "y = " line (make it a solid line for y ≤ or y ≥, and a dashed line for y < or y >)
- Shade above the line for a "greater than" (y > or y ≥) or below the line for a "less than" (y < or y ≤).
Calculation:
Given: The constraints –x + y ≤ 1, −x + 3y ≤ 9 and x, y ≥ 0
–x + y ≤ 1
⇒ y ≤ 1 + x
Hence shade below the line.
−x + 3y ≤ 9
3y ≤ 9 + x
⇒ y ≤ 3 + x/3
Hence shade below the line.
We can see through above graph region is unbounded feasible space
Last updated on Jul 4, 2025
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