Question
Download Solution PDFABCD దీర్ఘచతురస్రంలో, ADE అనేది 18 సె౦.మీ2 వైశాల్యం కలిగిన సమద్విబాహు త్రిభుజం. అదేవిధంగా, EC = 2 × DE. ఒకవేళ AD = DE అయితే ABCD యొక్క వైశాల్యం ఎంత?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDF⇒ ADE అనేది AD = DE = a అనే సమద్విబాహు త్రిభుజం.
ADE యొక్క ⇒ వైశాల్యం = 1/2 × AD × DE = 18
∴ 1/2 × a2 = 18
⇒ a = 6 సె౦.మీ
⇒ AD = DE = 6 సె౦.మీ
⇒ EC = 2 × DE = 2 × 6 = 12 సె౦.మీ
⇒ ∴ ABCD యొక్క వైశాల్యం = AD × DC = 6 × (DE + EC) = 6 × (6 + 12) = 108 సె౦.మీ2
Last updated on Jul 9, 2025
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