Question
Download Solution PDFദീർഘചതുരം ABCD യിൽ, 18 സെ.മീ2 വിസ്തീർണ്ണമുള്ള ഒരു സമപാർശ്വ ത്രികോണമാണ് ADE. കൂടാതെ, EC = 2 × DE. AD = DE ആണെങ്കിൽ, ABCD യുടെ വിസ്തീർണ്ണം എന്താണ്?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDF⇒ ADE എന്നത് ഒരു സമപാർശ്വ ത്രികോണമാണ്, ഇവിടെ AD = DE = a
⇒ ADE യുടെ വിസ്തീർണ്ണം = 1/2 × AD × DE = 18
∴ 1/2 × a2 = 18
⇒ a = 6 സെ.മീ.
⇒ AD = DE = 6 സെ.മീ
⇒ EC = 2 × DE = 2 × 6 = 12 സെ.മീ
∴ ABCD യുടെ വിസ്തീർണ്ണം= AD × DC = 6 × (DE + EC) = 6 × (6 + 12) = 108 സെ.മീ2Last updated on Jul 7, 2025
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