Starting from point X, a person walked 20 m towards South to reach point Y. From there, he took a left turn and walked 25 m to reach point Z. He then took a left turn and walked for another 20 m to reach point P. What is the approximate shortest distance between the points X and Z and in which direction is the person's final position with respect to point X?

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SSC Steno Previous Paper 18 (Held on: 23 Dec 2020 Shift 2)
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  1. 50 m, South-East
  2. 36 m, South-East
  3. 32 m, East
  4. 46 m, North-West

Answer (Detailed Solution Below)

Option 3 : 32 m, East
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SSC Steno 2022 Official Paper (Held On: 17 Nov 2022 Shift 1)
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Detailed Solution

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In the below diagram shortest distance between starting point x and point z denoted by point X and Z respectively.

F1 Prashant Ravi 10.03.21 D9

Now, Triangle "XYZ" is a right-angled triangle, so using Pythagoras Theorem:

XZ2 = XY2 + YZ2

XZ2 = (20)2 + (25)2

XZ2 = 400 + 625

XZ2 = 1025

XZ2= √ 1025

XZ = 32.015

XZ is approximately equal to 32

The person's final position P is in the east with respect to point X. 

Thus the shortest distance is 32 m and the final direction is in the east with respect to the starting point.

Hence, the correct answer is "32 m, East".

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