simplify:

\(-20\div\frac{4}{7}\ \rm of\ 55\frac{1}{8}\times\frac{9}{5}-\left(\frac{6}{7}+1\right)\).

This question was previously asked in
SSC MTS 2020 (Held On : 14 Oct 2021 Shift 1) Official Paper 22
View all SSC MTS Papers >
  1. \(\frac{5}{7}\)
  2. -3
  3. \(-\frac{200}{567}\)
  4. 3

Answer (Detailed Solution Below)

Option 2 : -3
Free
SSC MTS Mini Mock Test
1.7 Lakh Users
45 Questions 75 Marks 46 Mins

Detailed Solution

Download Solution PDF

Concept:

Follow BODMAS rule to solve this question, as per the order given below, 

619c84099b892b6172520023 16389656398191

Given:

\(-20÷\frac{4}{7}\ \rm of\ 55\frac{1}{8}×\frac{9}{5}-\left(\frac{6}{7}+1\right)\)

Calculation:

\(-20÷\frac{4}{7}\ \rm of\ 55\frac{1}{8}×\frac{9}{5}-\left(\frac{6}{7}+1\right)\)

⇒ - 20 ÷ 4/7 of 441/8 × 9/5 - 13/7 

⇒ - 20 ÷ 63/2 × 9/5 - 13/7

⇒ - 20 × 2/63 × 9/5 - 13/7 

⇒ - 8/7 - 13/7 

⇒ - 21/7 

⇒ - 3

∴ The required result is - 3. 

Latest SSC MTS Updates

Last updated on Jun 27, 2025

-> SSC MTS 2025 Notification has been released by the Staff Selection Commission (SSC) on the official website on 26th June, 2025.

-> A total of 1075 Vacancies have been announced for the post of Havaldar in CBIC and CBN.

-> The last date to apply online will be 24th July 2025 as per the SSC Exam Calendar 2025-26.

-> The selection of the candidates for the post of SSC MTS is based on Computer Based Examination. 

-> Candidates with basic eligibility criteria of the 10th class were eligible to appear for the examination. 

-> Candidates must attempt the SSC MTS Mock tests and SSC MTS Previous year papers for preparation.

Get Free Access Now
Hot Links: teen patti joy apk teen patti boss teen patti real cash withdrawal teen patti master plus teen patti game - 3patti poker