Power available due to an undisturbed wind of speed 10 m/s acting on a turbine rotor of diameter 10 m is 500 kW. What would be the power for a wind speed of 20 m/s?

Question

Question

This question was previously asked in

MPPGCL JE Electrical 28 April 2023 Shift 3 Official Paper

Answer 1

Concept

The power available in the wind is given by the formula:

P α v³

Using the proportionality:

\(({P_1\over P_2})=({v_1\over v_2})^3\)

Calculation

Given, P₁ = 500 kW at v₁ = 10 m/s

The power P₂ at v₂ = 20 m/s is calculated as:

\(({500\over P_2})=({10\over 20})^3\)

P2 = 500 × 8

P2 = 4000 kW

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