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Download Solution PDF5 च्या सलग तीन विभाज्यांची बेरीज 285 आहे. त्यातील सर्वात मोठी संख्या शोधा.
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5 च्या सलग तीन विभाज्यांची बेरीज 285 आहे
गणना:
तीन सलग संख्या x, x + 1 आणि x + 2 आहेत
तर, 5 चे सलग विभाज्य 5x, 5(x + 1) आणि 5(x + 2) आहेत
5 च्या सलग तीन विभाज्यांची बेरीज 285 आहे
∴ 5x + 5x + 5 + 5x + 10 = 285
⇒ 15x = 270
⇒ x = 18
आता, सर्वात मोठी संख्या = 5(x + 2) = 5 × 20 = 100
∴ सर्वात मोठी संख्या 100 आहेLast updated on Jul 2, 2025
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