Question
Download Solution PDFएका तलावाच्या पाण्यापासून 60 मीटर उंच बिंदूपासून पक्ष्याचा उन्नत कोन 30 ͦ आहे. त्याच बिंदूपासून पाण्याखाली पक्ष्याच्या प्रतिबिंबाचा उदासीन कोन 60 ͦ आहे. तलावाच्या भोवती फिरत असलेल्या पक्ष्याची उंची मीटरमध्ये शोधा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFBE ही पक्ष्याची तलावापासूनची उंची आहे.
⇒ BE = ED = h मीटर
⇒ AF = CE = 60 मीटर
⇒ BC = (h – 60) मीटर आणि CD = (h + 60) मीटर
ΔABC मध्ये,
tan 30 = BC/AC
⇒ 1/√3 = (h – 60)/AC
⇒ AC = √3 (h – 60) ----(i)
ΔADC मध्ये
tan 60 = CD/AC
⇒ √3 = (h + 60)/AC
⇒ AC = (h + 60)/√3 ----(ii)
समीकरण (i) आणि समीकरण (ii) वरून
√3 (h – 60) = (h + 60)/√3
⇒ 3 (h – 60) = (h + 60)
⇒ 3h – 180 – h = 60
⇒ 2h = 240
⇒ h = 120 मीटर
∴ तलावापासून पक्ष्याची उंची 120 मीटर आहे.
Last updated on Jul 18, 2025
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