कर्मचार्यांच्या वयाच्या मध्यम सममितीय वितरणासाठी, मध्य = 20 आणि बहुलक = 25 आहे. मध्यकाचे अंदाजे मूल्य आहे:

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SSC CGL Tier-II ( JSO ) 2019 Official Paper ( Held On : 17 Nov 2020 )
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  1. \(21\dfrac{1}{3}\)
  2. \(21\dfrac{2}{3}\)
  3. \(22\dfrac{1}{3}\)
  4. \(22\dfrac{2}{3}\)

Answer (Detailed Solution Below)

Option 2 : \(21\dfrac{2}{3}\)
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दिलेले आहे

मध्य = 20

बहुलक = 25

सुत्र

3 × मध्यक = बहुलक + 2 × मध्य

गणना

मध्यक = (बहुलक + 2 मध्य)/3

⇒ (25 + 2 × 20)/3

⇒ (25 + 40)/3

⇒ 65/3

∴ मध्यक = 21 2/3
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