In the given circuit the reading of voltmeter V1 and V2 are 300 volts each. The reading of the voltmeter V3 and ammeter A are respectively

F1 P.Y Madhu 06.07.20 D3

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  1. 100 V, 2.0 A
  2. 150 V, 2.2 A
  3. 220 V, 2.2 A
  4. 220 V, 2.0 A

Answer (Detailed Solution Below)

Option 3 : 220 V, 2.2 A
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Detailed Solution

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CONCEPT:

F1 P.Y 7.5.20 Pallavi D2

  • The ac circuit containing the capacitorresistor, and the inductor is called an LCR circuit.
  • For a series LCR circuit, the total potential difference of the circuit is given by:

\(V = \sqrt {{V_R^2} + {{\left( {{V_L} - {V_C}} \right)}^2}} \)

Where VR = potential difference across R, VL =  potential difference across L and VC =  potential difference across C

  • For a series LCR circuitImpedance (Z) of the circuit is given by:

\(\)\(Z = \sqrt {{R^2} + {{\left( {{X_L} - {X_C}} \right)}^2}} \)
Where R = resistance, XL =induvtive reactance and XC = capacitive reactive

CALCULATION:

Given - V= V= 300V and V = 220V

  • For a series LCR circuit, the total potential difference of the circuit is given by:

\(⇒ V = \sqrt {{V_3^2} + {{\left( {{V_1} - {V_2}} \right)}^2}} \)

\(⇒ 220 = \sqrt {{V_3^2} + {{\left( {{300} - {300}} \right)}^2}} =\sqrt {V^2_3}=V_3\)

⇒ V= 220V

  • The reading on the ammeter will be

\(⇒ I=\frac{V_3}{R}=\frac{220}{100}=2.2A\)

  • The reading on the voltmeter V3 will be 

⇒ V3 = IR

⇒ V3 = 2.2 × 100 = 220 V

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