In the figure, a very large plane sheet of positive charge is shown. P1 and P2 are two points at distance l and 2l from the charge distribution. If σ is the surface charge density, then the magnitude of electric fields E1 and E2 at P1 and P2 respectively are :

F1 Savita UG Entrance 19-9-22 D1

  1. E1 = σ/εo, E2 = σ/2 εo
  2. E1 = 2 σ/εo, E2 = σ/εo
  3. E1 = E2 = σ/2 εo
  4. E1 = E2 = σ/εo

Answer (Detailed Solution Below)

Option 3 : E1 = E2 = σ/2 εo
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Detailed Solution

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Explanation:

Given

F1 Savita UG Entrance 19-9-22 D1

We know that,

Electric field due to the uniformly charged large surface is given as:

E = σ/ 2ϵo  ----- (1)

From equation (1) it is clear that the electric field due to a uniformly charged surface is independent of distance from the surface.

It only depends on the surface density.

Hence in both cases, the Electric field will be the same, i.e.

E1 = E2 = σ/ 2ϵo

Hence option 3) is the correct choice.

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