Question
Download Solution PDFIn an isosceles triangle length of base is 20 cm and the altitude of the triangle is 20% more than the base. Find the length of each equal side.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Base of the triangle (b) = 20 cm
Altitude of the triangle (h) = 20% more than the base = 20 + (20 × 20 / 100) = 24 cm
Formula used:
In an isosceles triangle, the altitude divides the triangle into two right-angled triangles.
Using Pythagoras theorem:
Equal side (s) = √((b/2)2 + h2)
Calculations:
Equal side (s) = √((20/2)2 + 242)
⇒ s = √(102 + 242)
⇒ s = √(100 + 576)
⇒ s = √676
⇒ s = 26 cm
∴ The correct answer is option (4).
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