In a simple gear train, 1st gear (Driver) has 40 number of teeth, 2nd gear has 20 number of teeth and last gear has 80 number of teeth. The train value of the gear train is -

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  1. 0.5
  2. 1
  3. 2
  4. 1.2

Answer (Detailed Solution Below)

Option 1 : 0.5

Detailed Solution

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Concept:

Velocity Ratio is:

\(Velocity~ratio = \frac{{Speed~of~driver}}{{Speed~of~follower}}\)

Train value is:

The reciprocal of velocity ratio is known as train value of the gear train.

\(Train~value= \frac{1}{velocity~ratio}\)

The velocity ratio of a simple gear train

F1 Ashik Madhu 28.08.20 D13

When the driver and intermediate gear are in mesh

\(\frac{{{N_1}}}{{{N_2}}} = \frac{{{T_2}}}{{{T_1}}}\)

When the intermediate and followers are in mesh.

\(\frac{{{N_2}}}{{{N_3}}} = \frac{{{T_3}}}{{{T_2}}}\)

Multiplying both the equations,

\(\frac{{{N_1}}}{{{N_2}}} \times \frac{{{N_2}}}{{{N_3}}} = \frac{{{T_2}}}{{{T_1}}} \times \frac{{{T_3}}}{{{T_2}}}\)

\(\frac{{{N_3}}}{{{N_1}}} = \frac{{{T_1}}}{{{T_3}}}\)

\(Speed~ratio = \frac{{Speed~of~driver}}{{Speed~of~follower}} = \frac{{No.~of~teeth~on~follower}}{{No.~of~teeth~on~driver}}\)

Calculation:

Given:

T1 = 40, T2 = 20, T3 = 80

\(Velocity~ratio=\frac{{T_3}}{{T_1}} = \frac{{80}}{{40}} = 2\)

\(Train~value = \frac{{1}}{{velocity~ratio}} = \frac{1}{2} = 0.5\)

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