Question
Download Solution PDFIf there are 76 persons in a party and if they shake hands with each other, how many handshakes are possible
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The number of ways to select r things out of n things is given by nCr
\(\rm ^nC_r=\frac{n!}{(n-r)!×(r)!}=\frac{n×(n-1)×....(n-r+1)}{r!}\)
Calculation:
We have to select 2 persons out of 76 for handshakes.
\(\therefore \) Number of handshakes = \(\rm ^{76}C_2=\frac{76×75}{2× 1}\)
= 38 × 75
= 2850
Hence, option (3) is correct.
Last updated on Jun 18, 2025
->UPSC has extended the UPSC NDA 2 Registration Date till 20th June 2025.
-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.
->The NDA exam date 2025 has been announced. The written examination will be held on 14th September 2025.
-> The selection process for the NDA exam includes a Written Exam and SSB Interview.
-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100.
-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential.