If the distance between the plates of a parallel plate capacitor is halved keeping other parameters unchanged. The the new capacitance will become-

CONCEPT:

The capacitance of a capacitor (C):

• The capacitance of a conductor is the ratio of charge (Q) to it by a rise in its potential (V), i.e.

C = Q/V

• The unit of capacitance is the farad, (symbol F ).
• A parallel plate capacitor consists of two large plane parallel conducting plates of area A and separated by a small distance d.
• Mathematical expression for the capacitance of the parallel plate capacitor is given by:
• \(\Rightarrow C = \frac{{{\epsilon_o}A}}{d}\)

  Where C = capacitance, A = area of the two plates, εo = permittivity of free space, and d = separation between the plates,

Parallel Plate Capacitor:

EXPLANATION:

• The capacitance of the parallel plate capacitor is given by:

\(\Rightarrow C = \frac{{{\epsilon_o}A}}{d}\)     

• When the distance between the plates of a parallel plate capacitor is halved, the capacitance of the parallel plate capacitor will be

\(\Rightarrow C_1 = \frac{{{\epsilon_o}A}}{\frac{d}{2}}= \frac{{{2\epsilon_o}A}}{d}=2C\)      

• Hence, if the distance between the plates of a parallel plate capacitor is halved then the capacitance of the capacitor will become twice the initial capacitance.