Question
Download Solution PDFComprehension
Direction: Study the following information and answer the following questions.
Five persons are working in a bank. Their designations are CEO, CFO, Manager, Clerk, and Peon. The sequence of the posts is as above i.e. CEO is the senior most and Peon is the junior most person. They have a different number of pens. No two persons have the same number of pens.
Two persons are junior to Z. The difference in the number of pens between R and Z is 14 and Z has the least number of pens. The one who is just senior to the one who is Manager has 33 pens. A is just senior to the one who has 45 pens. There is one designation between the Manager and R. A has 11 pens more and 9 pen more than W and Q respectively. One designation lies between the one who has 33 pens and A.
How many pens does Clerk have?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
5 designations - CEO, CFO, Manager, Clerk, and Peon
CEO is the senior most and Peon is the juniormost person.
They have a different number of pens such that no two persons have the same number of pens.
Now,
1) Two persons are junior to Z. It means Z is a Manager.
2) The one who is just senior to the one who is Manager has 33 pens. It means CFO has 33 pens.
3) One designation lies between the one who has 33 pens and A. It means A is Clerk.
| Posts | Persons | Number of Pens |
| CEO | ||
| CFO | 33 | |
| Manager | Z | |
| Clerk | A | |
| Peon |
4) A is just senior to the one who has 45 pens. It means Peon has 45 pens.
5) There is one designation between the Manager and R. It means R can be either CEO or Peon.
Case I
| Posts | Persons | Number of Pens |
| CEO | R | |
| CFO | 33 | |
| Manager | Z | |
| Clerk | A | |
| Peon | 45 |
Case II
| Posts | Persons | Number of Pens |
| CEO | ||
| CFO | 33 | |
| Manager | Z | |
| Clerk | A | |
| Peon | R | 45 |
6) A has 11 pens more and 9 pens more than W and Q respectively. It means A = W+11 and A = Q+9. W+11 = Q+9. Q-W = 2. Q has more pens than W. In case I, Q has 45 pens and W has 33 pens. But 45-33 is not equal to 2. So, the case I get eliminated. In case II, again there are two possibilities:
Possibility I - W have 33 pens. So Q will have 35 pens and A will have 44 pens.
Possibility II - Q has 33 pens so W will have 31 pens and A will have 42 pens.
Case II (a)
| Posts | Persons | Number of Pens |
| CEO | Q | 35 |
| CFO | W | 33 |
| Manager | Z | |
| Clerk | A | 44 |
| Peon | R | 45 |
Case II (b)
| Posts | Persons | Number of Pens |
| CEO | W | 31 |
| CFO | Q | 33 |
| Manager | Z | |
| Clerk | A | 42 |
| Peon | R | 45 |
7) The difference in the number of pens between R and Z is 14 and Z has the least number of pens. So, R – 14 = Z. Z has 45-14 =31 pens. But no two persons can have the same number of pens. So, case II (b) gets eliminated as W also has 31 pens in it.
The final arrangement is -
| Posts | Persons | Number of Pens |
| CEO | Q | 35 |
| CFO | W | 33 |
| Manager | Z | 31 |
| Clerk | A | 44 |
| Peon | R | 45 |
Hence, The correct answer is 44.
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