नीचे दिए गए तर्क परिपथ का आउटपुट _______गेट को दर्शाता है।

F2 U.B Madhu 5.11.19 D 2

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SSC JE EE Previous Year Paper 14 (Held On: 26 Sep 2019 Morning)
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  1. OR
  2. NOR
  3. AND
  4. NAND

Answer (Detailed Solution Below)

Option 4 : NAND
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F1 U.B. Nita 11.11.2019 D 3

\(Q = \overline {AB} \)

आउटपुट समीकरण Q, NAND गेट के समकक्ष है।

 

Important Points

NAND GATE

चिन्ह:

F1 U.B Madhu 15.11.19 D 16

सत्य सारणी:

इनपुट A

इनपुट B

आउटपुट

\(Y = \overline {AB}\)

0

0

1

0

1

1

1

0

1

1

1

0

 

आउटपुट समीकरण: \(Y = \overline {A.B} = \overline A + \overline B\)

महत्वपूर्ण बिंदु:

1) यदि A सदैव उच्च होता है, तो आउटपुट अन्य इनपुट B अर्थात् B̅ का उल्टा मान होता है।

2) जब दोनों इनपुट उच्च होते हैं, केवल तभी आउटपुट निम्न होता है।

3) यह एक सार्वभौमिक गेट है।

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