Question
Download Solution PDFΔPQR एक समकोण त्रिभुज है। कोण PQR = 90° और QS ⊥ PR है। यदि PQ = 6 सेमी और PS = 4 सेमी है, तो QS की लम्बाई ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
कोण PQR = 90° और QS ⊥ PR है।
PQ = 6 सेमी और PS = 4 सेमी
प्रयुक्त अवधारणा:
समकोण त्रिभुज में,
कर्ण2 = आधार2 + लम्ब2
गणना:
त्रिभुज PQR = 90° और QS ⊥ PR है।
∴ QSP = 90°
QSP में पायथागोरस नियम का प्रयोग करने पर,
QS2 + SP2 = QP2
⇒ x2 + 42 = 62
⇒ x2 = 36 - 16
⇒ x = √ 20
⇒ x = 2√ 5
∴ सही उत्तर विकल्प 1 है।
Last updated on Jul 22, 2025
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