Question
Download Solution PDFसमलम्ब ABCD में, AD∥BC है, O, विकर्ण BD और AC का प्रतिच्छेदन बिंदु है। बिंदु F और E क्रमशः AB और CD पर इस प्रकार हैं कि FE बिंदु O से होकर जाती है। यदि BC = 5 सेमी और AD = 20 सेमी है, तो, EF की लंबाई है -
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
AD/BC
BC = 5 सेमी तथा AD = 20 सेमी
प्रयुक्त अवधारणा:
यदि AD = a तथा BC = b
⇒ EF = (2a.b)/(a + b)
गणना:
अतः, EF = (2 × AD × BC)/(AD + BC)
⇒ (2 × 20 × 5) /(20 + 5)
⇒ 200/25
⇒ 8 सेमी
Last updated on Jul 21, 2025
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