दिए गए चित्र में, MN = RM = RP, तब ∠MPR का मान (अंश में) क्या है?

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SSC CGL Previous Paper 10 (Held On: 10 August 2017 Shift 1)
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  1. 47
  2. 68
  3. 72
  4. निर्धारित नहीं किया जा सकता

Answer (Detailed Solution Below)

Option 2 : 68
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यहाँ, ΔPRM और ΔMRN समद्विबाहु त्रिकोण हैं।

और ΔRPN में

⇒ ∠RPM + ∠RNP = 102°         …….(i)       [बाह्य कोण गुण]

⇒ ∠MRN = ∠MNR

⇒ ∠MRN + ∠MNR = ∠RMP     ……(ii)        [बाह्य कोण गुण]

⇒ 2∠RNP = ∠RMP = ∠RPM     

(i) और (ii) से, हमें मिलता है

⇒ 3/2(∠RPM) = 102°

⇒ ∠RPM = 68°

∴ उचित विकल्प 2) है।

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