Question
Download Solution PDFआंतरिक वायरिंग अनुमान में, यदि जुड़ा हुआ भार 2 kW है और आपूर्ति वोल्टेज 240 V है, तो अधिकतम भार धारा _______ होगी।
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Detailed Solution
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आंतरिक वायरिंग अनुमान के लिए अधिकतम भार धारा इस प्रकार दी जाती है:
\(I={P\over V}\)
जहां, I = धारा
P = शक्ति
V = वोल्टेज
गणना
दिया गया है, P = 2kW = 2000 W
V = 240 वोल्ट
\(I={2000\over 240}=8.33 A\)
Last updated on Jul 1, 2025
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