Question
Download Solution PDFएक समबाहु ΔABC में, AD, BE तथा CF माध्यिकाएं बिंदु G पर एक दूसरे को काटती हैंI यदि चतुर्भुज BDGF का क्षेत्रफल 12√3 सेमी2 है, ΔABC की भुजा है:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
चतुर्भुज का क्षेत्रफल = 12√3 सेमी2
प्रयुक्त अवधारणा
हम जानते हैं कि, त्रिभुज का माध्य त्रिभुज को समान भागों में काटता है।
त्रिभुज का क्षेत्रफल = (√3/4) (भुजा)2
गणना:
⇒ ΔABC का क्षेत्रफल = चतुर्भुज BDGF का क्षेत्रफल × 3
⇒ ΔABC का क्षेत्रफल = 12√3 × 3
⇒ΔABC का क्षेत्रफल = 36√3 सेमी2
⇒ 36√3 = (√3/4) × (भुजा)2
⇒ भुजा = 12 सेमी
∴ ΔABC की भुजा 12 सेमी है।
Last updated on Jul 22, 2025
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