Question
Download Solution PDFतीन बच्चों वाले परिवार में, तीसरी संतान के लड़की होने की क्या प्रायिकता है, जबकि अन्य दो भी लड़कियां हैं?
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प्रायिकता = अनुकूल परिणाम/कुल परिणाम
गणना
तीन बच्चों वाला परिवार = G, G, G जहाँ G = लड़कियां
हम लड़की को 3C1 = \(\frac{3 !}{1! (3-1)!}\) के रूप के चुन सकते हैं
⇒ 3C1 = \(\frac{3 !}{1! (3-1)!}\) = 3
लड़की के चयन के संभावित तरीकों की संख्या \(\frac{^3 C _1}{2!}\) है
⇒ संभावित परिणाम = \(\frac 32\)
लड़की के चयन के कुल तरीकों की संख्या =3! = 3 × 2
⇒ कुल परिणाम = 6
प्रायिकता = अनुकूल परिणाम/कुल परिणाम
⇒ प्रायिकता = \(\frac{3/2}{6}=\frac{3}{ 2 \times 6} = \frac 14\)
∴ तीसरी संतान के लड़की होने की प्रायिकता 1/4 है, जबकि अन्य दो भी लड़कियां हैं।
Last updated on Jun 13, 2025
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