Question
Download Solution PDFएक 1.8°, 2-फेज द्विध्रुवी स्टेपर मोटर के लिए स्टेपिंग दर 100 स्टेप/सेकंड है। RPM में मोटर की घूर्णी गति क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFधारणा:
मोटर की गति \( = \frac{{β f}}{{360}}\)
स्टेपर मोटर में स्टेप कोण,
\(β = \frac{{\left( {{P_s} - {P_r}} \right)}}{{{P_s}{P_r}}} \times 360\)
जहाँ, Ps स्टेटर ध्रुवों की संख्या है
Pr रोटर ध्रुवों की संख्या है
f स्टेपिंग दर है
गणना:
दिया हुआ-
β = 1.8°, f = 100 steps/sec
मोटर की गति \( = \frac{{1.8 \times 100}}{{360}} = 0.5\;rps\)
इसलिए RPM में मोटर की घूर्णी गति = 0.5 x 60 = 30
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