Question
Download Solution PDFABCD एक समलंब है, जिसमें CD और AB की लंबाई 12 सेमी और 8 सेमी है। AC और BD विकर्ण हैं, जिनके मध्यबिंदु P और Q हैं। PQ की लंबाई ज्ञात कीजिए? (जहाँ, CD ∥ AB)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
AB = 8 सेमी
CD = 12 सेमी
AP = PC
BQ = QD
प्रयुक्त सूत्र:
एक समलंब के विकर्णों के मध्य बिंदुओं को मिलाने वाली रेखा की लंबाई = (लंबी समांतर भुजा - छोटी समांतर भुजा)/2
गणना:
PQ = (DC - AB)/2
⇒ (12 - 8)/2
⇒ 4/2
⇒ 2 सेमी
Last updated on Jul 19, 2025
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