Question
Download Solution PDFABCD हा एक समलंब चौकोन आहे, ज्यामध्ये CD आणि AB ची लांबी 12 सेमी आणि 8 सेमी आहे. AC आणि BD हे कर्ण आहेत, ज्यांचे मध्य बिंदू P आणि Q आहेत. तर PQ ची लांबी शोधा? (येथे, CD ∥ AB)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेले आहे:
AB = 8 सें.मी.
CD = 12 सें.मी.
AP = PC
BQ = QD
वापरलेले सूत्र:
समलंब चौकोनाच्या कर्णांच्या मध्यबिंदूंना जोडणाऱ्या रेषेची लांबी = (मोठी समांतर बाजू - लहान समांतर बाजू)/2
गणना:
PQ = (DC - AB)/2
⇒ (12 - 8)/2
⇒ 4/2
⇒ 2 सें.मी.
Last updated on Jul 19, 2025
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