Question
Download Solution PDFComprehension
The following table shows the number of males (M) and females (F) (in thousands) in Towns X and Y during the five years from 2018 to 2022. Based on the data in the table, answer the questions.
Year wise numbers of Males and Females in two Towns (in thousands)
Years |
Town X |
Town Y |
||
Number of males |
Number of females |
Number of males |
Number of females |
|
2018 |
50 |
49 |
53 |
50 |
2019 |
52 |
49 |
54 |
52 |
2020 |
55 |
52 |
55 |
54 |
2021 |
53 |
53 |
58 |
56 |
2022 |
55 |
52 |
62 |
55 |
For town Y, the percentage increase in the number of females for a given year with reference to the previous year is maximum in the year _____
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation:
Number of females in 2019 = 52
Number of females in 2018 = 50
⇒ Percentage increase = ((52 - 50) ÷ 50) × 100 = (2 ÷ 50) × 100 = 4%
Number of females in 2020 = 54
Number of females in 2019 = 52
⇒ Percentage increase = ((54 - 52) ÷ 52) × 100 = (2 ÷ 52) × 100 ≈ 3.85%
Number of females in 2021 = 56
Number of females in 2020 = 54
⇒ Percentage increase = ((56 - 54) ÷ 54) × 100 = (2 ÷ 54) × 100 ≈ 3.70%
Number of females in 2022 = 55
Number of females in 2021 = 56
⇒ Percentage increase = ((55 - 56) ÷ 56) × 100 = (-1 ÷ 56) × 100 ≈ -1.79%
∴ The percentage increase in the number of females for a given year with reference to the previous year is maximum in the year 2019.
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