Find the number of years in which the number of females in Town X and Y is less than their respective average numbers in these two towns.

Question

Question

Comprehension

The following table shows the number of males (M) and females (F) (in thousands) in Towns X and Y during the five years from 2018 to 2022. Based on the data in the table, answer the questions.

Year wise numbers of Males and Females in two Towns (in thousands)

Years	Town X		Town Y
Years	Number of males	Number of females	Number of males	Number of females
2018	50	49	53	50
2019	52	49	54	52
2020	55	52	55	54
2021	53	53	58	56
2022	55	52	62	55

Find the number of years in which the number of females in Town X and Y is less than their respective average numbers in these two towns.

This question was previously asked in

UGC NET Official Paper 1: Held On 14 June 2023 Shift 1

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One, two
Two, Two
Three, Two
Two, one

Answer 1

Concept used:

Average = Sum of observation / Number of observations

Calculation:

The average number of females in Town X in 5 years = \(\dfrac{49 + 49 + 52 + 53 + 52}{5} \) = 51

Average number of females in Town Y in 5 years = \(\dfrac{50 + 52 + 54 + 56 + 55}{5}\) = 53.4

⇒ In town X, in 2018 & 2019, the number of females are less than their average.

⇒ In town Y, in 2018 & 2019, the number of females are less than their average.

∴ The number of years in which the number of females in Town X and Y is less than their respective average numbers in these two towns is Two, Two.

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Question

Comprehension

Find the number of years in which the number of females in Town X and Y is less than their respective average numbers in these two towns.

Answer (Detailed Solution Below)

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