Determine the resistance of a 100 ft length of copper wire with a diameter of 20 mils. Assume resistivity ρ = 10.37 CM-Ω/ft

This question was previously asked in
MPPGCL JE Electrical 19 March 2019 Shift 2 Official Paper
View all MPPGCL Junior Engineer Papers >
  1. 41.48 Ω
  2. 5.29 Ω
  3. 48.41 Ω
  4. 2.59 Ω

Answer (Detailed Solution Below)

Option 4 : 2.59 Ω
Free
MPPGCL JE Electrical Fundamentals Mock Test
1 K Users
20 Questions 20 Marks 24 Mins

Detailed Solution

Download Solution PDF

Concept

The resistance of a wire is given by:

\(R=ρ{l\over A}\)

where, R = Resistance

ρ = Resistivity

l = Mean length per turn

A = Cross-sectional area

The area in circular mils is given by: 

Area = d2 , where d is diameter

Calculation

Given, d = 20 mils

Area = 400 cm

\(R=10.37\times {100\over 400}\)

R = 2.59 Ω

Latest MPPGCL Junior Engineer Updates

Last updated on Jul 18, 2025

-> MPPGCL Junior Engineer Notification 2025 has been released for various fields of post (Advt No. 3233).

-> MPPGCL has announced a total of 90 vacancies for Civil, Mechanical, Electrical, and Electronics Engineering (Junior Engineer).

->  Interested candidates can submit their online application form, from 23rd July to 21st August 2025. 

-> MPPGCL Junior Engineer result PDF has been released at the offiical website.

-> The MPPGCL Junior Engineer Exam Date has been announced.

-> The MPPGCL Junior Engineer Notification was released for 284 vacancies.

-> The selection process includes a Computer Based Test and Document Verification.

-> Candidates can check the MPPGCL JE Previous Year Papers which helps to understand the difficulty level of the exam.

More Network Elements Questions

Get Free Access Now
Hot Links: teen patti club apk teen patti stars teen patti master gold apk teen patti gold new version