Comprehension

Consider the following for the two (02) items that follow:

\(\text{Let } f(x)= \begin{cases} x^3, & x^2 < 1 \\ x^2, & x^2 \ge 1 \end{cases} \\\)

Consider the following statements:

I. The function is continuous at .

II. The function is differentiable at .

Which of the statements given above is/are correct?

This question was previously asked in
NDA-I (Mathematics) Official Paper (Held On: 13 Apr, 2025)
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  1. I only
  2. II only
  3. Both I and II
  4. Neither I nor II

Answer (Detailed Solution Below)

Option 4 : Neither I nor II
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Detailed Solution

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Calculation:

Given,

The function is defined as:

\( f(x) = \begin{cases} x^3, & \text{if} \, |x| < 1 \\ x^2, & \text{if} \, |x| \geq 1 \end{cases} \)

We are tasked with finding:

\( \lim_{x \to -1} f'(x) \)

Check the left-hand limit for continuity at x = -1 :

\( \lim_{x \to -1^-} f(x) = (-1)^2 = 1 \)

Check the right-hand limit for continuity at x = -1 :

\( \lim_{x \to -1^+} f(x) = (-1)^3 = -1 \)

Since the left-hand limit (L.H.S) and right-hand limit (R.H.S) are not equal, the function is discontinuous at x = -1 .

Check the differentiability at x = 1 :

The left-hand derivative at x = 1  is \(\text{L.H.D} = 3 \) and the right-hand derivative at  x = 1  is \(\text{R.H.D} = 2 \) which means the function is not differentiable at x = 1 

∴ The function is neither continuous at x = -1  nor differentiable at x = 1 . 

Hence, the correct answer is Option 4.

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