Question
Download Solution PDFComprehension
Consider the following for the two (02) items that follow:
\(\text{Let } f(x)= \begin{cases} x^3, & x^2 < 1 \\ x^2, & x^2 \ge 1 \end{cases} \\\)
Consider the following statements:
I. The function is continuous at .
II. The function is differentiable at .
Which of the statements given above is/are correct?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation:
Given,
The function is defined as:
\( f(x) = \begin{cases} x^3, & \text{if} \, |x| < 1 \\ x^2, & \text{if} \, |x| \geq 1 \end{cases} \)
We are tasked with finding:
\( \lim_{x \to -1} f'(x) \)
Check the left-hand limit for continuity at x = -1 :
\( \lim_{x \to -1^-} f(x) = (-1)^2 = 1 \)
Check the right-hand limit for continuity at x = -1 :
\( \lim_{x \to -1^+} f(x) = (-1)^3 = -1 \)
Since the left-hand limit (L.H.S) and right-hand limit (R.H.S) are not equal, the function is discontinuous at x = -1 .
Check the differentiability at x = 1 :
The left-hand derivative at x = 1 is \(\text{L.H.D} = 3 \) and the right-hand derivative at x = 1 is \(\text{R.H.D} = 2 \) which means the function is not differentiable at x = 1
∴ The function is neither continuous at x = -1 nor differentiable at x = 1 .
Hence, the correct answer is Option 4.
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