Calculate the mean hydraulic radius of an open channel whose cross -sectional area is 30 m2 and wetted perimeter is 80 m.

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DDA JE Civil 01 Apr 2023 Shift 3 Official Paper
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  1. 1.265 m
  2. 0.375 m
  3. 2.667 m
  4. 0.925 m

Answer (Detailed Solution Below)

Option 2 : 0.375 m
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Detailed Solution

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Explanation:

Hydraulic Radius \(= \frac{{{\rm{C}}/{\rm{S\;area}}}}{{{\rm{Wetted\;perimeter}}}} = \frac{{\rm{A}}}{{\rm{P}}} = {\rm{R}}\)

Hydraulic depth \(= \frac{{{\rm{C}}/{\rm{S\;area}}}}{{{\rm{Top\;width}}}} = \frac{{\rm{A}}}{{\rm{T}}}\)

Given:

A = 30 m2, P = 80 m

Calculation:

\({\rm{R}} = \frac{{\rm{A}}}{{\rm{P }}} = \frac{30}{80} = 0.375\)

 

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