According the kinetic theory of gases, which of the following relation between pressure (P) and volume (V) is correct? (M is mass and v is velocity of the gas particles)

  1. \(PV =\frac{1}{2}Mv^2\)
  2. \(P =\frac{1}{3}Mv^2\)
  3. \(PV =\frac{1}{3}Mv^2\)
  4. \(\rho =\frac{1}{2}Mv^2\)

Answer (Detailed Solution Below)

Option 3 : \(PV =\frac{1}{3}Mv^2\)
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option (3)

CONCEPT:

  • Kinetic theory of gases: It states that all gaseous molecules remain under random and continuous motion and the velocity of the particles depends on the temperature.
    • Using this theory various properties like pressure, temperature, the energy of the molecules can be explained.
    • ​Hence, this theory is called the Kinetic Theory of gases which were developed by Clausius and Maxwell.

\(PV =\frac{1}{2}Mv^2\) 

Where M is the mass of the particle, V is the volume and v is the velocity of the particles.

EXPLANATION:

  • According to Pascal's law, a gas transmits pressure equally in all directions and the pressure exerted by the gas is given by- 

\(P = \frac{1}{3} ρ v^2\)

we know that density = Mass/Volume

\(ρ=\frac{M}{V}\)

\(P=\frac{1}{3}{M}{V^2}v^2\)

  • \(PV =\frac{1}{3}Mv^2\) is the correct relation according to the kinetic theory of gases.

Additional Information

Assumption of Kinetic Theory:

  • Between two collisions a molecule moves in a straight path with a uniform velocity.
  • During the random motion, the molecules collide with one other with velocity remains unchanged.
  • The size of molecules is negligible compared to the distance between the molecules
  • The molecules are in a state of continuous random motion and they move all the possible directions with all the possible velocity. 

F1 Prabhu Madhu 04.09.20 D2

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