ABCD is a quadrilateral in which AB ∥ DC. E and F are the midpoints of the diagonals AC and BD, respectively. If AB = 18 cm and CD = 6 cm, then EF = ?

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SSC CGL Tier 2 Quant Previous Paper 1 (Held On: 29 Jan 2022)
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  1. 8 cm
  2. 9 cm
  3. 6 cm
  4. 12 cm

Answer (Detailed Solution Below)

Option 3 : 6 cm
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Detailed Solution

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Given:

ABCD is a quadrilateral in which AB ∥ DC.

E and F are the midpoints of the diagonals AC and BD

AB = 18 cm 

CD = 6 cm

Concept used:

The length of line joining midpoints of the diagonals is half the difference of the length of parallel sides of the trapezium.

Calculation:

F2-Savita SSC 11-5-22 D3

ABCD is a quadrilateral in which AB ∥ DC.

E and F are the midpoints of the diagonals AC and BD

We know that, the length of line joining midpoints of the diagonals is half the difference of the length of parallel sides of the trapezium.

So,

⇒ EF = \(\frac{1}{{2}} \)(Difference of its parallel sides)

⇒ EF = \(\frac{1}{{2}} \)(AB – DC)

⇒ EF = \(\frac{1}{{2}} \)(18 – 6)

⇒ EF = \(\frac{1}{{2}} \) × 12

⇒ EF = 6 cm

∴ The value of EF is 6 cm

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