ABC is a triangle and D is a point on the side BC. If BC = 16 cm, BD = 11 cm and ∠ADC = ∠BAC, then the length of AC is equal to:

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SSC CGL 2023 Tier-I Official Paper (Held On: 27 Jul 2023 Shift 2)
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  1. 4\(\sqrt5\) cm
  2. 4 cm
  3. 3\(\sqrt5\) cm
  4. 5 cm

Answer (Detailed Solution Below)

Option 1 : 4\(\sqrt5\) cm
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Detailed Solution

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Given:

BC = 16 cm, BD = 11 cm and ∠ADC = ∠BAC

Concept:

If two angles and a side of the two triangles are equal, then both triangles will be similar by AA property.

Calculation:

In ΔABC and ΔDAC

⇒ ∠ADC = ∠BAC

⇒ ∠C = Common angle in both triangle

So, ΔABC and ΔDAC are similar triangle.

⇒ \({BC\over AC}={AC\over DC}\)

⇒ AC2 = BC × DC

⇒ AC2 = 16 × 5 = 80

⇒ AC = 4√5

∴ The required result will be 4√5.

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