A right angled triangle of area 600 m2 is to be made such that the hypotenuse is double the base. For the triangle, the hypotenuse is ________ more than the base.

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SSC CHSL Exam 2024 Tier-I Official Paper (Held On: 11 Jul, 2024 Shift 4)
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  1. 24.36 m
  2. 26.32 m
  3. 22.32 m
  4. 20.36 m

Answer (Detailed Solution Below)

Option 2 : 26.32 m
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Detailed Solution

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Given:

Area of the right-angled triangle = 600 m2

Hypotenuse = 2 × Base

Hypotenuse > Base

Formula used:

Area of right-angled triangle = (1/2) × Base × Height

Pythagoras theorem: Hypotenuse2 = Base2 + Height2

Calculation:

Let the base be b meters.

Height = h meters.

Hypotenuse = 2b meters.

Area = (1/2) × b × h

600 = (1/2) × b × h

⇒ h = 1200 / b

Using Pythagoras theorem:

(2b)2 = b2 + (1200 / b)2

⇒ 4b2 = b2 + 1440000 / b2

⇒ 3b4 = 1440000

⇒ b4 = 480000

⇒ b2 = 692.82

⇒ b = 26.32 m

Hypotenuse = 2 × 26.32 = 52.64 m

Difference between hypotenuse and base = 52.64 - 26.32 = 26.32 m.

Therefore, hypotenuse is 26.32 m more than the base.

∴ The correct answer is option 2.

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