Question
Download Solution PDFA two-port network has parameters ABCD. If all the impedances in the network are doubled, then
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe ABCD/transmission parameters are given as:
\(\left[ {\begin{array}{*{20}{c}} {{V_1}}\\ {{I_1}} \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} A&B\\ C&D \end{array}} \right]\left[ {\begin{array}{*{20}{c}} {{V_2}}\\ { - {I_2}} \end{array}} \right]\)
The impedances are:
\(B = \frac{V_1}{I_2}\)
\(C=\frac{I_1}{V_2}\)
Since B is directly proportional to impedance and C is inversely proportional to the impedance.
∴ Doubling the impedances means, doubling B and also C gets halved, rest A and D are not affected.
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