Question
Download Solution PDFA potential barrier of 0.50 V exists across a p-n junction. If the depletion region is 5.0 × 10-7 m wide, what is the intensity of the electric field in this region?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe width of the depletion region is given as:
W = 5.0 × 10-7 m
The potential barrier (Vb) = 0.50 V
The intensity of the electric field in this region can be calculated as:
\(E=\frac{V_b}{W}=\frac{0.5}{5 × 10^{-7}}\)
= 1.0 × 106 V/m
Last updated on Jul 2, 2025
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