Question
Download Solution PDFA group of numbers and symbols is coded using letter codes as per the codes given below and the conditions that follow. Study the given codes and conditions and answer the question that follows.
Note: If none of the conditions apply, then codes for the respective number/symbol are to be followed directly as given in the table.
| Number/symbol | 2 | @ | 9 | 5 | $ | & | 3 | % | # | 7 | + | 4 | 8 | 6 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| Code | T | F | A | J | L | E | W | Q | D | P | R | B | U | S |
Conditions:
If the first element is a symbol and the last a number, the codes for these two (the first and the last elements) are to be interchanged.
If the first element is an odd number and the last an even number, the first and last elements are to be coded as ©.
If both second and third elements are perfect squares, the third element is to be coded as the code for the second element.
If none of the above conditions are met, then the elements are to be simply coded as per the codes given in the question. What will be the code for the following group?
@ 2 4 7 +
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven Group: @ 2 4 7 +
Coding Table:
| Number/symbol | 2 | @ | 9 | 5 | $ | & | 3 | % | # | 7 | + | 4 | 8 | 6 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| Code | T | F | A | J | L | E | W | Q | D | P | R | B | U | S |
Initial Codes for @ 2 4 7 +:
| Element | @ | 2 | 4 | 7 | + |
|---|---|---|---|---|---|
| Initial Code | F | T | B | P | R |
Applying Conditions (check against original elements):
Condition 1: If the first element is a symbol and the last a number, the codes for these two (the first and the last elements) are to be interchanged.
- First element: '@' (is a symbol). (True)
- Last element: '+' (is a symbol, not a number). (False)
- Condition 1 does NOT apply.
Condition 2: If the first element is an odd number and the last an even number, the first and last elements are to be coded as ©.
- First element: '@' (is a symbol, not an odd number). (False)
- Condition 2 does NOT apply.
Condition 3: If both second and third elements are perfect squares, the third element is to be coded as the code for the second element.
- Second element: '2' (is not a perfect square). (False)
- Condition 3 does NOT apply.
Conclusion:
Since none of the above conditions are met, the elements are to be simply coded as per the codes given in the table.
Final Code:
The code for the group @ 2 4 7 + is F T B P R.
Hence, the correct answer is "Option 4".
Last updated on Jul 19, 2025
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