A body starts to fall freely under gravity. The distances covered by it in first, second and third second are in ratio

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AIIMS BSc NURSING 2023 Memory-Based Paper
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  1. 1 ∶ 3 ∶ 5
  2. 1 ∶ 2 ∶ 3
  3. 1 ∶ 4 ∶ 9
  4. 1 ∶ 5 ∶ 6

Answer (Detailed Solution Below)

Option 1 : 1 ∶ 3 ∶ 5
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When a body falls freely under gravity, the distance covered in the nth second is given by the formula:

Distance covered in nth second = u + (2gs) (where u is the initial velocity, g is the acceleration due to gravity, and s is the time interval)

For a body falling from rest, u = 0. So, the distance covered in nth second is:

s = (1/2) × g × (2n - 1)

The distances covered in the first, second, and third seconds are in the ratio:

1st second: (1/2) × g × (2 × 1 - 1) = g/2

2nd second: (1/2) × g × (2 × 2 - 1) = 3g/2

3rd second: (1/2) × g × (2 × 3 - 1) = 5g/2

So, the ratio of distances covered in the first, second, and third seconds is:

1 : 3 : 5

Thus, the correct option is Option 1: 1 : 3 : 5

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